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Question
The Laplace transform of exp(at), where a > 0, is defined only for the Laplace parameter, s > a since
Options:
A .  The Laplace transform integral of exp(at) has initial values only for s > a
B .  The Laplace transform of integral of exp(at) has finite values only for s > a
C .  The function is exponential
D .  The function exp(at) is piece-wise continuous only for s > a
Answer: Option B
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