Question
The greatest of the numbers $√^2{8}, √^4{13}, √^5{16}, √^10{41}$ is:
Answer: Option D
Answer: (d)$√^2{8}, √^4{13}, √^5{16}, √^10{41}$LCM of 2, 4, 5 and 10 = 20$√^2{8}=√^20{8^10}; √^4{13}=√^20{13^5}$$√^5{16}=√^20{16^4}; √^10{41}=√^20{41^2}$Clearly, $√^2{8}$ is the largest.
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Answer: (d)$√^2{8}, √^4{13}, √^5{16}, √^10{41}$LCM of 2, 4, 5 and 10 = 20$√^2{8}=√^20{8^10}; √^4{13}=√^20{13^5}$$√^5{16}=√^20{16^4}; √^10{41}=√^20{41^2}$Clearly, $√^2{8}$ is the largest.
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