Question
The expression $2^{6n} – 4^{2n}$, where n is a natural number is always divisible by
Answer: Option C
Answer: (c)$2^{6n} – 4^{2n}$ = $(2^6)^n - (4^2)^n $ = $64^n – 16^n$ which is divisible by 64 –16= 48
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Answer: (c)$2^{6n} – 4^{2n}$ = $(2^6)^n - (4^2)^n $ = $64^n – 16^n$ which is divisible by 64 –16= 48
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