Question
The expression $2^{6n} – 4^{2n}$, where n is a natural number is always divisible by
Answer: Option C
Answer: (c)$2^{6n} – 4^{2n}$ = $(2^6)^n - (4^2)^n $ = $64^n – 16^n$ which is divisible by 64 –16= 48
Was this answer helpful ?
Answer: (c)$2^{6n} – 4^{2n}$ = $(2^6)^n - (4^2)^n $ = $64^n – 16^n$ which is divisible by 64 –16= 48
Was this answer helpful ?
More Questions on This Topic :
Question 3. Fraction between $2/5$ and $4/9$ is :....
Question 6. $2/3$ of three-fourth of a number is :....
Question 9. Half of 1 per cent written as a decimal is—....
Submit Solution