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Question

The difference of two numbers is 11 and one-fifth of their sum is 9. Find the numbers.



Options:
A .  27 and 27
B .  25 and 16
C .  29 and 17
D .  28 and 17
Answer: Option D

Let the number be x and y. Then,
x−y = 11----(i)and 1/5(x+y)=9↔x+y= 45----(ii)
Adding (i) and (ii), we get: 2x = 56 or x = 28. Putting x = 28 in (i), we get: y = 17.
Hence, the numbers are 28 and 17.




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