Question
The compound interest on a certain sum of money for 2 years at 10% per annum is Rs.420. The simple interest on the same sum at the same rate and for the same time will be
Answer: Option A
Answer: (a)If the principal be P thenC.I. = P$[(1 + R/100)^T - 1]$420 = P$[(1 + 10/100)^2 - 1]$420 = P$({121 - 100}/100)$420 = ${P × 21}/100$P = ${420 × 100}/21$ = Rs.2000S.I. = ${PRT}/100 = {2000 × 10 × 2}/100$ = Rs.400Using Rule 10,Here, C.I. = Rs.420, R = 10%, S.I. = ?C.I. = S.I.$(1 + R/200)$420 = S.I.$(1 + 10/200)$420 = S.I.$(210/200)$S.I. = ${420 × 200}/210$ = Rs.400
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Answer: (a)If the principal be P thenC.I. = P$[(1 + R/100)^T - 1]$420 = P$[(1 + 10/100)^2 - 1]$420 = P$({121 - 100}/100)$420 = ${P × 21}/100$P = ${420 × 100}/21$ = Rs.2000S.I. = ${PRT}/100 = {2000 × 10 × 2}/100$ = Rs.400Using Rule 10,Here, C.I. = Rs.420, R = 10%, S.I. = ?C.I. = S.I.$(1 + R/200)$420 = S.I.$(1 + 10/200)$420 = S.I.$(210/200)$S.I. = ${420 × 200}/210$ = Rs.400
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