Question
The compound interest on a certain sum of money for 2 years at 5% per annum is Rs.410. The simple interest on the same sum at the same rate and for the same time is
Answer: Option B
Answer: (b)Compound interest = P $[(1 + R/100)^T - 1]$410 = P$[(1 + 5/100)^2 - 1]$410 = P$[(1 + 1/20)^2 - 1]$410 = P$[(21/20)^2 - 1]$410 = P$(441/400 - 1)$410 = P$(41/400)$P = ${410 × 400}/41$ = Rs.4000S.I. = $\text"Principal × Time × Rate"/100$= ${4000 × 2 × 5}/100$ = Rs.400Using Rule 10,Here, C.I. = Rs.410, R = 5%, S.I. = ?C.I. = S.I.$(1 + R/200)$410 = S.I.$(1 + 5/200)$410 = S.I.$(205/200)$S.I. = ${410 × 200}/205$ = Rs.400
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Answer: (b)Compound interest = P $[(1 + R/100)^T - 1]$410 = P$[(1 + 5/100)^2 - 1]$410 = P$[(1 + 1/20)^2 - 1]$410 = P$[(21/20)^2 - 1]$410 = P$(441/400 - 1)$410 = P$(41/400)$P = ${410 × 400}/41$ = Rs.4000S.I. = $\text"Principal × Time × Rate"/100$= ${4000 × 2 × 5}/100$ = Rs.400Using Rule 10,Here, C.I. = Rs.410, R = 5%, S.I. = ?C.I. = S.I.$(1 + R/200)$410 = S.I.$(1 + 5/200)$410 = S.I.$(205/200)$S.I. = ${410 × 200}/205$ = Rs.400
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