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Question

The area of the incircle of an equilateral triangle of side 42 cm is :


Options:
A .  `22sqrt(3)`` cm^2`
B .  `231`` cm^2`
C .  `462``cm^2`
D .  `924 ``cm^2`
Answer: Option C

Radius of incircle =  `(a)/(2sqrt(3)) = (42)/(2sqrt(3)) cm =  7sqrt(3) `cm

Area of incircle = `(22/7 xx 49 xx 3) cm^2 = 462 cm^2`




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