Question
Solving 52+x+1y−4=2; 62+x−3y−4=1,
we get
x = ___
y = ___
Answer: Option A
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Let, p = 12+x and q = 1y−4
Thus, given equations reduce to,
5p+q=2 ... (i)
6p−3q=1 ... (ii)
On multiplying (i) by 3 and then adding it to (ii), we get
15p+3q=6
6p−3q=1
_______________
21p=7
⇒p=13
and on substituting this value in (ii) we get
613−3q=1
⇒q=13
Now, p=12+x
⇒13=12+x
⇒x=1
We know that q=1y−4
⇒13=1y−4
⇒y=7
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