Question
$√{3√{3√{3...}}}$ is equal to
Answer: Option B
Answer: (b)Let x = $√{3√{3√{3...}}}$Squaring both sides,$x^2 = 3√{3√{3√{3...}}}$ = 3x$x^2$ - 3x = 0x (x - 3) = 0x = 3 because x ≠ 0Using Rule 23$√{x√{x√{x...n times}}}= x^(1-1/{x^n})$
Was this answer helpful ?
Answer: (b)Let x = $√{3√{3√{3...}}}$Squaring both sides,$x^2 = 3√{3√{3√{3...}}}$ = 3x$x^2$ - 3x = 0x (x - 3) = 0x = 3 because x ≠ 0Using Rule 23$√{x√{x√{x...n times}}}= x^(1-1/{x^n})$
Was this answer helpful ?
More Questions on This Topic :
Question 1. $√{6+√{6+√{6 +...}}}$ is equal to....
Question 2. $√{1+√{1+√{1 +...}}}$....
Question 3. $√{12+√{12+√{12 +...}}}$ is equal to....
Question 7. $√{2+√{2+√{2 +...}}}$ is equal to....
Submit Solution