On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder.

Question

On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:

Options:

A . 10

B . 11

C . 12

D . 13

Answer: Option A

Clearly, (2272 - 875) = 1397, is exactly divisible by N.

Now, 1397 = 11 x 127

The required 3-digit number is 127, the sum of whose digits is 10.

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