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Question

Of two numbers, 4 times the smaller one is less then 3 times the 1arger
one by 5. If the sum of the numbers is larger than 6 times their
difference by 6, find the two numbers.



Options:
A .  59 and 43
B .  55 and 40
C .  49 and 43
D .  60 and 33
Answer: Option A

Let the numbers be x and y, such that x↔y
Then,3x- 4y = 5....(i) and (x + y) - 6 (x - y) >= 6 =↔-5x + 7y = 6.....(ii)
Solving (i) and (ii), we get: x = 59 and y = 43.
Hence, the required numbers are 59 and 43.




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