Question
Of two numbers, 4 times the smaller one is less then 3 times the 1arger
one by 5. If the sum of the numbers is larger than 6 times their
difference by 6, find the two numbers.
Of two numbers, 4 times the smaller one is less then 3 times the 1arger
one by 5. If the sum of the numbers is larger than 6 times their
difference by 6, find the two numbers.
Answer: Option A
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Let the numbers be x and y, such that x↔y
Then,3x- 4y = 5....(i) and (x + y) - 6 (x - y) >= 6 =↔-5x + 7y = 6.....(ii)
Solving (i) and (ii), we get: x = 59 and y = 43.
Hence, the required numbers are 59 and 43.
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