Question
If (232 + 1) is completely divisible by a whole number, which of the following
numbers is completely divisible by this number?
Answer: Option A
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Let 232 = x. Then (232 + 1) = (x + 1)
Assume that (x + 1) is completely divisible by a whole number, N
(296 + 1) = {(232)3 + 1} = (x3 + 1) = (x + 1)(x2 - x + 1)
if (x + 1) is completely divisible by N, (x + 1)(x2 - x + 1) will also be divisible by N
Hence (296 + 1) is completely divisible N
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