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Mr Thomas invested an amount of Rs. 13,900  divided in two  different schemes A and B at the simple interest rate of 14% p.a.and 11% p.a.   respectively. If the total amount of simple interest earned in 2 years be Rs. 3508. What was the amount invested in Scheme B ?


Options:
A .  Rs. 6400
B .  Rs. 6500
C .  Rs. 7200
D .  Rs. 7500
E .  None of these
Answer: Option A

Let the sum invested in scheme A be Rs. `x` and that in Scheme B be Rs. (13900 - `x`).

Then,`((x xx 14 xx 2)/(100)) + [((13900 - x) xx 11 xx 2)/(100)] = 3508`

`hArr      28x - 22x = 350800 - (13900 xx 22)`

`hArr     6x =  45000`

`hArr     x = 7500`

So, sum invested in Scheme B  = Rs. (13900 - 7500) =  Rs.  6400



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