Question
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Mr. Thomas invested an amount of Rs. 13,900 divided in two different schemes A and B at the simple interest rate of 14% p.a. and 11% p.a. respectively. If the total amount of simple interest earned in 2 years be Rs. 3508, what was the amount invested in Scheme B?
Answer: Option A
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Answer : Option A
Explanation :
Let the investment in scheme A be Rs.x
and the investment in scheme B be Rs.(13900 - x)
$MF#%\begin{align}&\text{We know that }\text{SI = }\dfrac{\text{PRT}}{100}\\\\ &\text{Simple Interest for Rs.x in 2 years at 14% p.a. = }\dfrac{x \times 14 \times 2}{100} = \dfrac{28x}{100}\\\\ &\text{Simple Interest for Rs.(13900 - x) in 2 years at 11% p.a. = }\dfrac{(13900 - x) \times 11 \times 2}{100} = \dfrac{22(13900 - x)}{100}\\\\ &\text{Total interest = Rs.3508}\\\\ &\dfrac{28x}{100} + \dfrac{22(13900 - x)}{100} = 3508\\\\ &28x + 305800 -22x = 350800\\\\ &6x = 45000\\\\ &x = \dfrac{45000}{6} = 7500\end{align}$MF#%
Investment in scheme B = 13900 - 7500 = Rs.6400
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