Question
limπ→∞∑nr=1 1nern is [AIEEE 2004]
Answer: Option B
:
B
limπ→∞∑nr=11nern=∫10exdx=[ex]10=e−1
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:
B
limπ→∞∑nr=11nern=∫10exdx=[ex]10=e−1
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