Question
It is being given that (`2^32` + 1) is completely divisible by a whole number. Which of the following numbers is completely divisible by this number ?
Answer: Option D
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Let `2^32` = `x` , Then , (`2^32` + 1) = (`x` + 1)
Let (`x` + 1) be completely divisible by the natural number N. Then,
(`2^96` + 1) = [`(2^32)^3` + 1] = (`x^3` + 1) = (`x` + 1)(`x^2` - `x` + 1), which is completely divisible by N,
since (`x` + 1) is divisible by N.
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