Question
In how many years will the simple interest on a sum of money be equal to the principal at the rate of $$16\frac{2}{3}$$ % per annum ?
Answer: Option C
$$\eqalign{
& {\text{16}}\frac{2}{3} = \frac{{1 \to {\text{ Interest}}}}{{6 \to {\text{ Principal }}}} \cr
& {\text{Let principal = 6}} \cr
& {\text{Interest = 6}} \cr
& {\text{Time = t years}} \cr
& {\text{By using formula }} \cr
& {\text{6}} = \frac{{6 \times 50 \times {\text{t}}}}{{3 \times 100}} \cr
& \Rightarrow {\text{t}} = 6\,{\text{years}} \cr} $$
Alternate
Note : In such type of questions to save your valuable time think like the given way.
$$\eqalign{
& {\text{Rate}}\% \cr
& {\text{ = 16}}\frac{2}{3}\% = \frac{{1 \to {\text{ Interest}}}}{{6 \to {\text{ Principal }}}} \cr
& {\text{Represent for 1 years}} \cr
& {\text{According to the question,}} \cr
& {\text{Principal = Interest}} \cr
& {\text{6 = 1}} \times {\text{6}} \cr
& {\text{Hence,}} \cr
& {\text{Time = 1}} \times {\text{6}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 6 years}} \cr} $$
Note : If interest will be six times then time will also be six times.
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$$\eqalign{
& {\text{16}}\frac{2}{3} = \frac{{1 \to {\text{ Interest}}}}{{6 \to {\text{ Principal }}}} \cr
& {\text{Let principal = 6}} \cr
& {\text{Interest = 6}} \cr
& {\text{Time = t years}} \cr
& {\text{By using formula }} \cr
& {\text{6}} = \frac{{6 \times 50 \times {\text{t}}}}{{3 \times 100}} \cr
& \Rightarrow {\text{t}} = 6\,{\text{years}} \cr} $$
Alternate
Note : In such type of questions to save your valuable time think like the given way.
$$\eqalign{
& {\text{Rate}}\% \cr
& {\text{ = 16}}\frac{2}{3}\% = \frac{{1 \to {\text{ Interest}}}}{{6 \to {\text{ Principal }}}} \cr
& {\text{Represent for 1 years}} \cr
& {\text{According to the question,}} \cr
& {\text{Principal = Interest}} \cr
& {\text{6 = 1}} \times {\text{6}} \cr
& {\text{Hence,}} \cr
& {\text{Time = 1}} \times {\text{6}} \cr
& \,\,\,\,\,\,\,\,\,\,\,\,{\text{ = 6 years}} \cr} $$
Note : If interest will be six times then time will also be six times.
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