Question
In how many years will Rs. 2000 amounts to Rs. 2420 at 10% per annum compound interest?
Answer: Option C
$$\eqalign{
& {\text{Principal = Rs. 2000}} \cr
& {\text{Amount = Rs. 2420}} \cr
& {\text{Rate = 10% }} \cr
& {\text{By using formula,}} \cr
& \Rightarrow 2420 = 2000{\left( {1 + \frac{{10}}{{100}}} \right)^n} \cr
& \Rightarrow \frac{{2420}}{{2000}} = {\left( {1 + \frac{{10}}{{100}}} \right)^n} \cr
& \Rightarrow \frac{{121}}{{100}} = {\left( {\frac{{11}}{{10}}} \right)^n} \cr
& \Rightarrow {\left( {\frac{{11}}{{10}}} \right)^2} = {\left( {\frac{{11}}{{10}}} \right)^n} \cr
& \Rightarrow n = 2 \cr
& {\text{Hence,}} \cr
& {\text{required time = 2 years}} \cr} $$
Alternative
Note : In such type of questions to save your valuable time follow the given below method.
Principal
:
Amount
Ratio
→
2000
:
2420
100
:
121
$${\text{Rate = 10% = }}\frac{1}{{10}}$$
Principal
:
Amount
1st year
→
10
:
11
2nd year
→
10
:
11
Ratio
→
100
:
121
Note : Now after 2nd year both the principal and amount will be in the same ratio.
Hence required time = 2 years
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$$\eqalign{
& {\text{Principal = Rs. 2000}} \cr
& {\text{Amount = Rs. 2420}} \cr
& {\text{Rate = 10% }} \cr
& {\text{By using formula,}} \cr
& \Rightarrow 2420 = 2000{\left( {1 + \frac{{10}}{{100}}} \right)^n} \cr
& \Rightarrow \frac{{2420}}{{2000}} = {\left( {1 + \frac{{10}}{{100}}} \right)^n} \cr
& \Rightarrow \frac{{121}}{{100}} = {\left( {\frac{{11}}{{10}}} \right)^n} \cr
& \Rightarrow {\left( {\frac{{11}}{{10}}} \right)^2} = {\left( {\frac{{11}}{{10}}} \right)^n} \cr
& \Rightarrow n = 2 \cr
& {\text{Hence,}} \cr
& {\text{required time = 2 years}} \cr} $$
Alternative
Note : In such type of questions to save your valuable time follow the given below method.
Principal
:
Amount
Ratio
→
2000
:
2420
100
:
121
$${\text{Rate = 10% = }}\frac{1}{{10}}$$
Principal
:
Amount
1st year
→
10
:
11
2nd year
→
10
:
11
Ratio
→
100
:
121
Note : Now after 2nd year both the principal and amount will be in the same ratio.
Hence required time = 2 years
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