Question
In how many years will a sum of money double itself at 18.75% per annum simple interest?
Answer: Option B
$$\eqalign{
& {\text{Let sum = Rs}}{\text{. }}x{\text{}} \cr
& {\text{Then,}} \cr
& {\text{S}}{\text{.I}}{\text{. = Rs}}{\text{. }}x{\text{}} \cr
& \therefore \text{Time} = \left( {\frac{{100 \times {\text{S}}{\text{.I}}{\text{.}}}}{{{\text{P}} \times {\text{R}}}}} \right) \cr
& = \left( {\frac{{100 \times x}}{{x \times 18.75}}} \right){\text{years}} \cr
& = \frac{{26}}{3}{\text{years}} \cr
& = 5\frac{1}{3}{\text{years}} \cr
& = {\text{5 years 4 months}}{\text{}} \cr} $$
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$$\eqalign{
& {\text{Let sum = Rs}}{\text{. }}x{\text{}} \cr
& {\text{Then,}} \cr
& {\text{S}}{\text{.I}}{\text{. = Rs}}{\text{. }}x{\text{}} \cr
& \therefore \text{Time} = \left( {\frac{{100 \times {\text{S}}{\text{.I}}{\text{.}}}}{{{\text{P}} \times {\text{R}}}}} \right) \cr
& = \left( {\frac{{100 \times x}}{{x \times 18.75}}} \right){\text{years}} \cr
& = \frac{{26}}{3}{\text{years}} \cr
& = 5\frac{1}{3}{\text{years}} \cr
& = {\text{5 years 4 months}}{\text{}} \cr} $$
Was this answer helpful ?
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