Answer: Option C
:
C
Let us redraw the given figure as follows:

Now we know that interior angles on the same side of the transversal are supplementary
Therefore $\angle$BAO + $\angle$AOR = 180${}^{\circ }$
⇒ $\angle$AOR = 72${}^{\circ }$
and similarly 
$\angle$ROC + $\angle$OCD = 180${}^{\circ }$
 ⇒ $\angle$ROC + 120${}^{\circ }$ = 180${}^{\circ }$
 ⇒ $\angle$ROC = 60${}^{\circ }$
Hence
$\angle$AOC = 60${}^{\circ }$ + 72${}^{\circ }$
⇒ $\angle$AOC = 132${}^{\circ }$