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Question

If the velocity of projection is 4 m/sec and the angle of projection is `alpha^circ`, the maximum height of the projectile from a horizontal plane, is
Options:
A .  `(u^2 cos^2 alpha)/(2g)`
B .  `(u^2 sin^2 alpha)/(2g)`
C .  `(u^2 tan^2 alpha)/(2g)`
D .  `(u^2 sin 2alpha)/(2g)`
Answer: Option B



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