Question
If the compound interest on a certain sum for two years at 12% per annum is Rs.2,544, the simple interest on it at the same rate for 2 years will be
Answer: Option B
Answer: (b)C.I. = P$[(1 + R/100)^T - 1]$2544 = P$[(1 + 12/100)^2 - 1]$2544 = P$[(28/25)^2 - 1]$2544 = P$(784/625 - 1)$2544 = P$({784 - 625}/625)$2544 = ${P × 159}/625$P = ${2544 × 625}/159$ = Rs.10000S.I. = ${P × R × T}/100$= ${10000 × 2 × 12}/100$ = Rs.2400Using Rule 10,Here, C.I. = Rs.2544, R = 12%, S.I. = ?C.I. = S.I.$(1 + R/200)$2544 = S.I.$(1 + 12/200)$2544 = S.I.$(212/200)$S.I. = ${2544 × 200}/212$ = Rs.2400
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Answer: (b)C.I. = P$[(1 + R/100)^T - 1]$2544 = P$[(1 + 12/100)^2 - 1]$2544 = P$[(28/25)^2 - 1]$2544 = P$(784/625 - 1)$2544 = P$({784 - 625}/625)$2544 = ${P × 159}/625$P = ${2544 × 625}/159$ = Rs.10000S.I. = ${P × R × T}/100$= ${10000 × 2 × 12}/100$ = Rs.2400Using Rule 10,Here, C.I. = Rs.2544, R = 12%, S.I. = ?C.I. = S.I.$(1 + R/200)$2544 = S.I.$(1 + 12/200)$2544 = S.I.$(212/200)$S.I. = ${2544 × 200}/212$ = Rs.2400
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