Question
If the compound interest on a certain sum for 2 years at 4% p.a. is Rs.102, the simple interest at the same rate of interest for two years would be
Answer: Option A
Answer: (a)If the sum be P, thenC.I. = P$[(1 + R/100)^T - 1]$102 = $[(1 + 4/100)^2 - 1]$102 = P$[(26/25)^2 - 1]$102 = P$(676/625 - 1)$102 = P$({676 - 625}/625)$102 = P × $51/625$P = ${102 × 625}/51$ = Rs.1250S.I. = ${1250 × 2 × 4}/100$ = Rs.100
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Answer: (a)If the sum be P, thenC.I. = P$[(1 + R/100)^T - 1]$102 = $[(1 + 4/100)^2 - 1]$102 = P$[(26/25)^2 - 1]$102 = P$(676/625 - 1)$102 = P$({676 - 625}/625)$102 = P × $51/625$P = ${102 × 625}/51$ = Rs.1250S.I. = ${1250 × 2 × 4}/100$ = Rs.100
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