If n is a natural number, then (6n 2 + 6n) is always divisible by: Options: A . &nbspBoth 6 and 12 B . &nbsp6 only C . &nbsp12 only D . &nbspNone of these

Answer: Option A 6n 2 + 6n = 6n(n + 1) Hence 6n 2 + 6n is always divisible by 6 and 12 (âˆµ remember that n(n + 1) is always even)

If n is a natural numb

Question

If n is a natural number, then (6n² + 6n) is always divisible by:

Options:

A . Both 6 and 12

B . 6 only

C . 12 only

D . None of these

Answer: Option A

6n² + 6n = 6n(n + 1)
Hence 6n² + 6n is always divisible by 6 and 12 (âˆµ remember that n(n + 1) is always even)

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