Question
If n is a natural number, then (6n2 + 6n) is always divisible by:
If n is a natural number, then (6n2 + 6n) is always divisible by:
Answer: Option A
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6n2 + 6n = 6n(n + 1)
Hence 6n2 + 6n is always divisible by 6 and 12 ( remember that n(n + 1) is always even)
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