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Question

How many natural numbers between 17 and 80 are divisible by 6 ?


Options:
A .  4
B .  5
C .  6
D .  7
Answer: Option C

These numbers are 18, 24, 30, 36...........,78.

This is an  A.P. in which  a = 18,  d = (24 - 18) = 6   and  `l` = 78

Let the number of these terms be n. Then

`t_n = 78  rArr     a + (n -  1) d = 78`

`rArr   18 + (n - 1) xx 6 = 78`

`rArr     (n - 1) xx 6 = 60`

`rArr    (n - 1) = 10`

`rArr  n = 11`

Required number of numbers = 11 .



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