Answer : Option B

Explanation :

⁴³/₆ = 7, remainder = 1. Hence 5 more should be added to 43 to get the minimum
number divisible by 6 between 43 and 200.
=> Minimum number divisible by 6 between 43 and 200 = 43 + 5 = 48
²⁰⁰/₆ = 33, remainder = 2. Hence 2 should be decreased from 200 to get the maximum
number divisible by 6 between 43 and 200.
=> Maximum number divisible by 6 between 43 and 200 = 200 - 2 = 198
Hence, with a = 48, d = 6, l=198

$MF#%\text{Number of terms }= \dfrac{(l-a)}{d} + 1 = \dfrac{(198-48)}{6} + 1 = \dfrac{150}{6} + 1 = 25 + 1 = 26$MF#%