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Question

How many natural numbers are there between 43 and 200 which are exactly divisible by 6?
Options:
A .  28
B .  26
C .  24
D .  22
Answer: Option B

Answer : Option B

Explanation :

43/6 = 7, remainder = 1. Hence 5 more should be added to 43 to get the minimum
number divisible by 6 between 43 and 200.
=> Minimum number divisible by 6 between 43 and 200 = 43 + 5 = 48
200/6 = 33, remainder = 2. Hence 2 should be decreased from 200 to get the maximum
number divisible by 6 between 43 and 200.
=> Maximum number divisible by 6 between 43 and 200 = 200 - 2 = 198
Hence, with a = 48, d = 6, l=198

$MF#%\text{Number of terms }= \dfrac{(l-a)}{d} + 1 = \dfrac{(198-48)}{6} + 1 = \dfrac{150}{6} + 1 = 25 + 1 = 26$MF#%



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