Question
How many 3 digit numbers are divisible by 6 in all ?
Answer: Option B
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Required numbers are 102, 108, 114, ......, 996
This is an A. P. in which a = 102, d = 6 and l = 996.
Let the number of terms be n. Then ,
a + (n - 1)d = 996 `rArr` 102 + (n-1) x 6 = 996
`rArr` 6 x (n - 1) = 894 `rArr` (n - 1) =149 `rArr` n = 150
Required number of terms = 150
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The sum of first 45 natural numbers is :
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