Answer: Option A
:
Given that six employees left in 2002.
246 + 6 - 217 = 35 employees joined in 2002.
Also $6\times 5=30$ employees joined in 2000.
Similarly, $306+\frac{35}{5}-293$
i.e., 20 employees joined in 2004.
Given that four female employees left in 2000.
102 + 4 - 82 = 24 female employees joined in2000.
Also $4\times 4=16$ female employees joined in 1998.
Similarly, 115 + 24 - 105 =16 female employees
Let the number of employees left in 2003 and 2005 be x and y respectively.
293 + x - 246 = 47 + x is the number of employees who joined in 2003.
Similarly, 152 + x - 115 = 37 + x is the number of female employees who joined in 2003.
$\frac{(47+x)}{5}=\frac{(37+x)}{4}$
[As number of employees and female employees left in 2005 are equal]
x = 3
50 employees and 40 female employees joined in 2003.
As 3 left in 2003, $3\times 5=15$ employees and $3\times 4=12$ female employees joined in 2001.
Also, 219 + 15 - 217 = 17 employees and 102 + 12 - 105 = 9 female employees left in 2001.
85 employees of which 36 were females joined in 1999.
The following table gives the number of employees who joined each year:
$\begin{array}{ccccccc}Year& 1999& 2000& 2001& 2002& 2003& 2004\\ Employees& 85& 30& 15& 35& 50& 20\\ FemaleEmployees& 36& 24& 12& 16& 40& 16\end{array}$
16 female employees joined in 2004
Female employees who left from 2000 to 2006

= 4 + 9 + 6 + 3 + 4 + 10 + 4 = 40