For how many of the five products is the cost per unit more than the average c

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For how many of the five products is the cost per unit more than the average cost of all the given products?

Options:

A . 1

B . 2

C . 3

D . 4

Answer: Option A
:
A

Cost per unit of A = $\frac{(\frac{19}{100}) \times 11}{(\frac{24}{100}) \times 4000}$ = 217
Cost per unit of C = $\frac{(\frac{18}{100}) \times 11}{(\frac{19}{100}) \times 4000}$ = 148
Cost per unit of D = $\frac{(\frac{20}{100}) \times 11}{(\frac{17}{100}) \times 4000}$ = 229
Cost per unit of E = $\frac{(\frac{20}{100}) \times 11}{(\frac{22}{100}) \times 4000}$ = 229
Average cost of all the given products = $\frac{(217 + 427 + 148 + 229 + 229)}{5}$ = $\frac{1250}{5}$ = 250.
Therefore, only for B, the cost per unit is more than the average cost of all the given products.

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