Question
Find three consecutive numbers such that twice the first, three times the second and four times the third together make 191.
Answer: Option A
Answer: (a)Numbers = x, x +1 and x + 22x + 3x + 3 + 4x + 8 = 1919x = 191 – 11 = 180x = 20∴ Numbers = 20, 21 and 22
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Answer: (a)Numbers = x, x +1 and x + 22x + 3x + 3 + 4x + 8 = 1919x = 191 – 11 = 180x = 20∴ Numbers = 20, 21 and 22
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