Question
Find the numbers such that the square of number is 15 lesser than twice the number.
Answer: Option C
:
C and D
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C and D
Let the number be x.
Square of number: x2
Lesser by 15: x2−15
of two times the number: x2−15=2x
We get, x2−15=2x
Lets solve, x2−2x−15=0x2−5x+3x−15=0x(x−5)+3(x−5)=0(x−5)(x+3)=0∴x=5 & x=−3
The number satisfying the given statement are 5 & −3.
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