Question
Find the remainder when `2^31 ` is divided by 3. ?
Answer: Option A
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`2^31` = `(2^10 xx 2^10 xx 2^10) xx 2`
=`(2^10)^3 xx 2`
=`(1024)^3 xx 2`
Unit digit in `2^31` = Unit digit in `[(1024)^3 xx 2]` = (4 x 2)
= 8.Now , 8 when divided by 5 gives 3 as remainder.
`:.` `2^31` when divided by 5 gives remainder = 3.
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