Find the least fraction, which must be multiplied to (124 −12

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Question

Find the least fraction, which must be multiplied to $(1 \frac{2}{4} - \frac{1}{2} + 3 \frac{6}{16} - \frac{1}{16} + \frac{2}{8}$ ) to make it an integer.

Options:

A .

\frac{24}{1}

B .

\frac{16}{1}

C .

\frac{73}{1}

D .

\frac{1}{73}

Answer: Option B
:
B

$(1 \frac{2}{4}$ - $\frac{1}{2}$ +3 $\frac{6}{16}$ - $\frac{1}{16}$ + $\frac{2}{8}$ )

= $\frac{6}{4} - \frac{1}{2} + \frac{54}{16} - \frac{1}{16} + \frac{2}{8}$

Taking LCM of denominators and solving,

$\frac{24 - 8 + 54 - 1 + 4}{16}$ = $\frac{73}{16}$

Now, If we multiply $\frac{73}{16}$ by $\frac{16}{1}$ , it becomes 73, which is an integer

Hence, $\frac{16}{1}$ is the required fraction.

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