Question
Difference between the squares of two consecutive odd integers is always divisible by
Difference between the squares of two consecutive odd integers is always divisible by
Answer: Option A
Was this answer helpful ?
Answer : Option A
Explanation :
-----------------------------------------------------------------
Solution 1
------------------------------------------------------------------
Let two odd numbers be (2n - 1) and (2n + 1)
Difference between the squares
= (2n + 1)2 - (2n - 1)2
= [4n2 + 4n + 1] - [4n2 - 4n + 1]
= 8n which is always divisible by 8
-----------------------------------------------------------------
Solution 2
------------------------------------------------------------------
Take any two odd numbers, say 1 and 3
Difference between the squares = 32 - 12 = 9 - 1 = 8
From the given choices, now you can easily figure out the answer as 8
Was this answer helpful ?
More Questions on This Topic :
Question 1.
3897 x 999 = ?
....
Question 2.
? + 3699 + 1985 - 2047 = 31111
....
Question 3.
(12345679 x 72) = ?
....
Latest Videos
Latest Test Papers
Submit Solution