Let the parts be `x, y and (2379 - (x + y)]`

`x + (x xx 2 xx 5/100) =  y + (y xx 3 xx 5/100) =  z + (z xx 4 xx 5/100)`

`rArr      (11x)/(10)  =  (23y)/(20)  = (6z)/(5)  = k`

`rArr      x = (10k)/(11),    y = (20k)/(23),      z = (5k)/(6)`

But   `x + y + z`  = 2379

`rArr   (10k)/(11) + (20k)/(23) + (5k)/(6)  = 2379`

`rArr     1380k + 1320k + 1265k =  2379 xx 11 xx 23 xx 6`

`rArr      k = (2379 xx 11 xx 23 xx 6)/(3965) =  (3 xx 11 xx 23 xx 6)/(5)`

`:.`  `  x = (10/11 xx (3 xx 11 xx 23 xx 6)/(5))` =  828.

Hence , the first part is Rs. 828 .