Question
David intvested certain amount in three different schems A, B and C with the rate of interest 10% p.a. respectively.If the total interest accrued in one year was Rs. 3200 and the amount invested in scheme C was 150% of the amount invested in Scheme A and 240% of the amount invesed in Scheme B , what was the amount invested in Scheme B ?
Answer: Option A
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Let `x, y and z` be the amounts invested in schemes A, B and C respecivelt, Then ,
`((x xx 10 xx 1)/(100)) + ((y xx 12 xx 1)/(100)) + ((z xx 15 xx 1)/(100)) = 3200`
`hArr 10x + 12y + 15z = 320000`...................................................(i)
Now , z = 240% of y = `12/5 y` ......................................................(ii)
And, z = 150% of `x = 3/2 x` `rArr x = 2/3 z = (2/3 xx 12/5)y = 8/5 y` .............................(iii)
From (i), (ii) and (iii), we have .
16y + 12y + 36y = 320000
`hArr 64y = 320000 hArr y = 5000`
`:.` Sum invested in scheme B = Rs 5000.
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