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Construction of a ΔACB similar to ΔACB is shown in the figure below, which condition is used to construct AC ||AC?
Construction Of A ΔA′C′B Similar To ΔACB Is Shown In T...


Options:
A .   Corresponding angles are equal
B .   Alternate interior angles are equal
C .   Co-interior angles are supplementary
D .   Perpendicular bisector theorem
Answer: Option A
:
A
Here we construct AC||AC by making ACB=ACB and we used the corresponding angle property (if corresponding angles of two lines are equal, then the lines are parallel).

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