Answer: Option A
Answer: (a)
We have 3 patterns :
I. ABCD ….. XYZ, which occurs only once.
II. YX ….. BA, which repeats alternately.
III. BC ….. YZ, which repeats alternately.
Now, I has 26 terms.
So, number of terms before the desired term = (999 - 26) = 973.
Each of the patterns which occurs after
I, has 25 letters. Now, 973 + 25 gives quotient = 38 and remainder = 23.
Thus, the 1000th term of the given series is the 24th term of the 39th pattern after I.
Clearly, the 39th pattern is II and its 24th term is B.