Question
At which sum the simple interest at the rate of $$3\frac{3}{4}$$ % per annum will be Rs. 210 in $$2\frac{1}{3}$$ years?
Answer: Option B
$$\eqalign{
& {\text{S}}{\text{.I}}{\text{.}} = {\text{Rs}}{\text{. 210}} \cr
& {\text{R}} = 3\frac{3}{4}\% = \frac{{15}}{4}\% \cr
& {\text{T}} = {\text{2}}\frac{{\text{1}}}{{\text{3}}}{\text{years}} = \frac{7}{3}{\text{years}} \cr
& \therefore {\text{Sum}} = {\text{Rs}}{\text{.}}\left( {\frac{{100 \times 210}}{{\frac{{15}}{4} \times \frac{7}{3}}}} \right) \cr
& = {\text{Rs}}{\text{.}}\left( {\frac{{100 \times 210 \times 4 \times 3}}{{15 \times 7}}} \right) \cr
& = {\text{Rs}}{\text{. }}2400 \cr} $$
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$$\eqalign{
& {\text{S}}{\text{.I}}{\text{.}} = {\text{Rs}}{\text{. 210}} \cr
& {\text{R}} = 3\frac{3}{4}\% = \frac{{15}}{4}\% \cr
& {\text{T}} = {\text{2}}\frac{{\text{1}}}{{\text{3}}}{\text{years}} = \frac{7}{3}{\text{years}} \cr
& \therefore {\text{Sum}} = {\text{Rs}}{\text{.}}\left( {\frac{{100 \times 210}}{{\frac{{15}}{4} \times \frac{7}{3}}}} \right) \cr
& = {\text{Rs}}{\text{.}}\left( {\frac{{100 \times 210 \times 4 \times 3}}{{15 \times 7}}} \right) \cr
& = {\text{Rs}}{\text{. }}2400 \cr} $$
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