Question
At a certain rate of simple interest, a certain sum of money becomes double of itself in 10 years. It will become treble of itself in
Answer: Option D
Answer: (d)If principal be x, interest = xand rate = r% p.a. thenRate = ${SI × 100}/\text"Principal × Time"$= ${x × 100}/{x × 10}$ = 10%Now, p = x, interest = 2xThen, time = ${SI × 100}/\text"Principal × Rate"$= ${2x × 100}/{x × 10}$ = 20 yearsUsing Rule 3,R = ${(2 - 1)}/10$ × 100%R = 10%T = ${(n - 1)}/R × 100$ years= ${3 - 1}/10 × 100$ = 20 years.
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Answer: (d)If principal be x, interest = xand rate = r% p.a. thenRate = ${SI × 100}/\text"Principal × Time"$= ${x × 100}/{x × 10}$ = 10%Now, p = x, interest = 2xThen, time = ${SI × 100}/\text"Principal × Rate"$= ${2x × 100}/{x × 10}$ = 20 yearsUsing Rule 3,R = ${(2 - 1)}/10$ × 100%R = 10%T = ${(n - 1)}/R × 100$ years= ${3 - 1}/10 × 100$ = 20 years.
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