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Question
Arranging the following in ascending order $3^34, 2^51, 7^17$ we get
Options:
A .  $7^17 > 2^51 > 3^34$
B .  $2^51 > 3^34 > 7^17$
C .  $3^34 > 7^17 > 2^51$
D .  $3^34 > 2^51 > 7^17$
Answer: Option A
Answer:(d)$3^34 = (3^2)^17 = 9^17$$2^51 = (2^3)^17 = 8^17$$7^17 = 7^17$Clearly, $9^17 > 8^17 > 7^17$i.e., $3^34 > 2^51 > 7^17$

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