Question
A triangle and a parallelogram are constructed on the same base such that their areas are equal . if the altitude of the parallelogram is 100 m , then the altitude of the triangle is :
Answer: Option D
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Let the altitude of the triangle be `h_1` and base of each be b.
Then, `1/2 xx b xx h_1 = b xx h_2`, where `h_2` = 100 m
`hArr h_1 = 2h_2` = (2 x 100) m = 200 m
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