Question
A trader marked the selling price of an article at 10% above the cost price. At the time of selling, he allows certain discount and suffers a loss of 1%. He allowed the discount of :
Answer: Option A
Answer: (a)Let C.P. be 100Marked price = 110x% of 110 = 11x = ${11 × 100}/110$ = 10%Using Rule 8,Here, loss % = 1%, r = 10%, $r_1$ = x%loss % = ${r × (100 - r_1)}/100 - r_1$–1 = ${100 × (100 - x)}/100 - x$(–ve sign for loss)–100 = 1000 - 10x - 100x+110x = 1100x = 10% ⇒ r1 =10%
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Answer: (a)Let C.P. be 100Marked price = 110x% of 110 = 11x = ${11 × 100}/110$ = 10%Using Rule 8,Here, loss % = 1%, r = 10%, $r_1$ = x%loss % = ${r × (100 - r_1)}/100 - r_1$–1 = ${100 × (100 - x)}/100 - x$(–ve sign for loss)–100 = 1000 - 10x - 100x+110x = 1100x = 10% ⇒ r1 =10%
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