Question
A sum of money doubles in 12 years. In how many years, it will treble at S.I.
A sum of money doubles in 12 years. In how many years, it will treble at S.I.
Answer: Option D
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Answer : Option D
Explanation :
$MF#%\text{Simple Interest, SI = }\dfrac{\text{PRT}}{100}$MF#%
i.e, SI ∠T when rate(R) and principal (P) are constants
Let x be the sum of money and which will treble in n years
(Please note that when the money doubles, simple interest is 2x - x = x
and when the money trebles, simple interest is 3x - x = 2x)
(2x-x) ∠12
=> x ∠12 -------------(1)
(3x-x) ∠n
=> 2x ∠n -------------(2)
From (1) and (2),
$MF#%\dfrac{x}{2x} = \dfrac{12}{n}\\\\ \dfrac{1}{2} = \dfrac{12}{n}\\\\ \Rightarrow \text{n = 24 years}$MF#%
i.e, in 24 years, the money will treble.
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