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Question

A square is inscribed in a circle whose radius is 4 cm . The area of the portion  between the circle and the square

is :


Options:
A .  `(8 pi - 16)`
B .  `(8 pi - 32)`
C .  `(16 pi - 16)`
D .  `(16pi - 32)`
Answer: Option D

Given  R = 4 cm .  R = `1/2` x (diagonal of the square)

`hArr `    diagonal  =  2 R = 8 cm.

Required area = `pi R^2 - 1/2  xx (8)^2`

                         = `(pi xx 16 - 32)`

                         = `(16 pi - 32) cm^2`   



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