Question

A square and an equilateral triangle have equal perimeters . If the diagonal of the square is `12sqrt(2) cm^2`, then the area of the triangle is :


Options:
A .  `24sqrt(2) cm^2`
B .  `24sqrt(3) cm^2`
C .  `48sqrt(3) cm^2`
D .  `64sqrt(3) cm^2`
Answer: Option D

Let the side of the square be a cm.

Then its diagonal  = `sqrt(2) a cm`

Now , `sqrt(2) a =  12sqrt(2)`

`rArr     a = 12 cm`

perimeter of the square  = 4a =  48 cm.  perimeter of the equilateral triangle =  48 cm.

Each side of the triangle = 16 cm .

Area of the triangle = `(sqrt(3)/4 xx 16 xx 16)cm^2 =  (64sqrt(3)) cm^2`



Was this answer helpful ?
Next Question

Submit Solution

Your email address will not be published. Required fields are marked *

Latest Videos

Latest Test Papers