Question
A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is:
Answer: Option A
4 | x z = 6 x 1 + 4 = 10
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5 | y -2 y = 5 x z + 3 = 5 x 10 + 3 = 53
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6 | z - 3 x = 4 x y + 2 = 4 x 53 + 2 = 214
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| 1 - 4
Hence, required number = 214.
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4 | x z = 6 x 1 + 4 = 10
-----------
5 | y -2 y = 5 x z + 3 = 5 x 10 + 3 = 53
-----------
6 | z - 3 x = 4 x y + 2 = 4 x 53 + 2 = 214
-----------
| 1 - 4
Hence, required number = 214.
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