Question
A number was divided successively in order by 4, 5 and 6. The remainders were 2, 3 and 4 respectively. What is the number?
A number was divided successively in order by 4, 5 and 6. The remainders were 2, 3 and 4 respectively. What is the number?
Answer: Option D
Was this answer helpful ?
Answer : Option D
Explanation :
Let P be the number
Given that
P ÷ 4 = Q, remainder = 2
Q ÷ 5 = R, remainder = 3
R ÷ 6 = 1, remainder = 4
Hence R = 1 × 6 + 4 = 10
Q = 5R + 3 = (5 × 10) + 3 = 53
P = 4Q + 2 = (4 × 53) + 2 = 212 + 2 = 214
Was this answer helpful ?
More Questions on This Topic :
Question 2.
612
×
612....
Question 3.
397 x 397 + 104 x 104 + 2 x 397 x 104 = ?
....
Question 4.
-84 x 29 + 365 = ?
....
Question 8.
What is the unit digit in 771 ?
....
Latest Videos
Latest Test Papers
Submit Solution