Question
A number was divided successively in order by 4, 5 and 6. The remainders were respectively 2, 3 and 4. The number is:
Answer: Option A
Was this answer helpful ?
4 | x z = 6 x 1 + 4 = 10 ----------- 5 | y -2 y = 5 x z + 3 = 5 x 10 + 3 = 53 ----------- 6 | z - 3 x = 4 x y + 2 = 4 x 53 + 2 = 214 ----------- | 1 - 4 Hence, required number = 214.
Was this answer helpful ?
More Questions on This Topic :
Question 1.
(35423 + 7164 + 41720) - (317 x 89) = ?
....
Question 7.
A inve....
Question 8.
1 + 2 + 3 + ... + 12 = ?
....
Question 10.
12 + 22 + 32 + ... + 82 = ?
....
Latest Videos
Latest Test Papers
Submit Solution